#include<stdio.h>
#include<conio.h>
int main()
{
int x,z;
printf("Enter number : ");
scanf("%d", &x);
z=(x!=100 ? 1 : 0);
printf("d :",z);
getch();
}
/*In the above program !NOT operator is used with the conditional operator.The value of x is also
entered.Here,is the value of x is other than 100,then 1 assigned to z otherwise 0.*/
In this program, the user is prompted to enter a number using the scanf()
function. The value of x
is then evaluated using the logical NOT (!
) operator in conjunction with the conditional operator (?
). If x
is not equal to 100, the expression x!=100
returns true
, and the value 1 is assigned to the variable z
. If x
is equal to 100, the expression x!=100
returns false
, and the value 0 is assigned to z
. Finally, the value of z
is displayed to the user using the printf()
function. The program terminates with the use of the getch()
function which waits for a user to press a key on the keyboard.
Thanks
Write a program to display 1 if the inputted no. is except 100 otherwise 0.Use the logical NOT (!)